Limiting reagents
Get balanced Chemical equation
CH4 + 2O2 ----} CO2 + 2H2 O
Calculate how many moles of each reactant you have
.250 mol CH4 burned in 1.25o mol O2. Find the limiting reagent.
-calculate how much of one reactant you need to use up all of the other
*we need 2 * 0.250 mol of o2 to completely use up the CH4 we have more than that.
CH4 is the limiting reagent
2Ch3 CHO(1) + O2 -------} 2HC2H3O2(1)
m 4o g 20g
m 44.06 mol 32.00 g mol +1 6o.o6 g mol +1
n 0.908 mol .625 mol
How many grams of HC2H3O2(1) will be produced?
CH3CHO
How many grams of excess reactant will remain?
O2
0.908 mol * 1 mol O2/ 2 mol CH3HO
O2 needed: 0.454 mol
O2 had: 0.625 mol
CH3 CHO is limiting reagent
O2 is x.5
Get balanced Chemical equation
CH4 + 2O2 ----} CO2 + 2H2 O
Calculate how many moles of each reactant you have
.250 mol CH4 burned in 1.25o mol O2. Find the limiting reagent.
-calculate how much of one reactant you need to use up all of the other
*we need 2 * 0.250 mol of o2 to completely use up the CH4 we have more than that.
CH4 is the limiting reagent
2Ch3 CHO(1) + O2 -------} 2HC2H3O2(1)
m 4o g 20g
m 44.06 mol 32.00 g mol +1 6o.o6 g mol +1
n 0.908 mol .625 mol
How many grams of HC2H3O2(1) will be produced?
CH3CHO
How many grams of excess reactant will remain?
O2
0.908 mol * 1 mol O2/ 2 mol CH3HO
O2 needed: 0.454 mol
O2 had: 0.625 mol
CH3 CHO is limiting reagent
O2 is x.5